TV Shows - Fiona Dolman
Sorted by online popularity, based on the Engagement Score on December 21, 2024. Fiona Dolman has appeared in 1 television series with data.
  • Midsomer Murders Poster
    #420
    Midsomer Murders
    as Sarah Barnaby 5 episodes • #420 most popular show
    Midsomer Murders is a British television detective drama series that follows the investigations of Detective Chief Inspector John Barnaby as he unravels a series of mysterious and often bizarre murders in the fictional county of Midsomer. The show, which first aired in 1997, is known for its picturesque rural setting and complex murder mysteries. With its signature blend of suspense, dark humor, and intriguing character dynamics, Midsomer Murders appeals to fans of both crime dramas and cozy mysteries.
Movies - Fiona Dolman
Sorted by online popularity. Fiona Dolman has appeared in 0 movies with data.
    History of daily visits to Fiona Dolman's Wikipedia page
    Fiona Dolman Biography
    Fiona Dolman (born January 30, 1970) is a Scottish actress known for her roles in various television series. She gained recognition for portraying Miss Pamela Andrews in the ITV daytime drama series The Royal and its spinoff, The Royal Today. Dolman also played the character of Jackie Rosemary Lambert Bradley, PC Mike Bradley's solicitor wife, in the popular series Heartbeat. Additionally, she appeared in Channel 4's vampire serial Ultraviolet and the BBC show Paradox. In August 2010, Dolman had a brief role as a Police sergeant in the BBC series Waterloo Road. Since April 2011, she has been portraying Sarah Barnaby, wife of DCI John Barnaby, and the new head teacher at Causton Comprehensive School in Midsomer Murders. Dolman is also known for her appearance on Lily Savage's Blankety Blank. In 2019, she completed the London Marathon in memory of her father, raising a substantial amount of money for Hospice UK, of which she is an Ambassador.

    On December 21, 2024, Fiona Dolman had 400 Wikipedia visits, making them the #9,830 most popular actor online.